As you complete the lab, record your answers in this template. Save the document as LastName_FirstName_BIO1020_W5A3, and submit it to the Dropbox. Full lab instructions and the rubric with which you will be evaluated can be found in the online classroom.
Activity
The laws of segregation, independent assortment, and dominance form the basis of all genetics. The ability to predict the results of crossing experiments and explain any variance between expected and observed results is still a vital part of our understanding of heredity. In this lab assignment you will experiment with monohybrid crosses and explore the role of chance in genetics.
Experiment 1
Questions
Parent 1
Y
Y
Parent 2
Y
YY
YY
y
Yy
yy
Parent 1
Y
Y
Parent 2
Y
Yy
Yy
y
Yy
Yy
Y Y and Y y
Y Y and y y
The resulting phenotypes is that all the offsprings are yellow because all the offspring have at least one Y (yellow, dominant) allele
All the offsprings are yellow
There are no blue kernels in either cross and all are yellow because the genotypes of all the kernels have at least one dominant (Y) gene which codes for yellow color.
Parent 1
Y
Y
Parent 2
y
Yy
Yy
y
Yy
Yy
The genotypes of offsprings are Yy (heterozygous) and their proportion is 100% If Y= yellow an y= blue, then the phenotypes of the off springs would be the characteristics of Y gene which means all the off springs will have a yellow color.
Experiment 2
Questions
As you select the beads from the beaker, complete this table with each cross. You may complete the associated Punnett Squares on paper, but do not need to submit them as part of this lab.
Parents – randomly selected
F1 – determined from Punnett square
Cross
Genotype parent #1
Genotype parent #
4 Genotypes
4 Phenotypes
1
yy
yy
yy
yy
2
Yy
yY
YY
Yy
3
Yy
YY
YY
YY
4
yY
yy
Yy
yy
5
yy
YY
Yy
Yy
Possible Genotype
Parents
Offspring
YY
3
4
Yy
3
10
yy
4
6
Total
10
20